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markdown: Link the twitter response code docs inline.
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@ -412,6 +412,7 @@ def fetch_tweet_data(tweet_id: str) -> Optional[Dict[str, Any]]:
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except twitter.TwitterError as e:
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t = e.args[0]
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if len(t) == 1 and ('code' in t[0]):
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# https://developer.twitter.com/en/docs/basics/response-codes
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code = t[0]['code']
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if code in [34, 144, 421, 422]:
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# All these "correspond with HTTP 404," and mean
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